Let's analyze the given statements using logic:

1. All bloops are razzies.
   - Let's denote bloops as B and razzies as R. This statement can be written as: 
     \( B \subseteq R \) (i.e., all elements in set B are included in set R).

2. No razzies are lazzies.
   - Let's denote lazzies as L. This statement means there is no overlap between the sets R and L.
     \( R \cap L = \emptyset \) (i.e., the intersection of sets R and L is empty).

Given that \( B \subseteq R \) and \( R \cap L = \emptyset \), we can reason:
- Since all bloops are razzies, they fall within set R.
- Since no members of set R (razzies) can be in set L (lazzies), no members of set B (bloops, which are a subset of R) can be in set L either.

Therefore, it can be concluded that:
- No bloops can be lazzies (\( B \cap L = \emptyset \) ).

So, indeed, no bloops can be lazzies.
