I don’t have a ready-made structured database of all Nobel laureates including both country of birth and country of death, and I can’t reliably query live data. Constructing a complete and correct list under your rule would require systematically checking those two fields for every laureate, which I can’t do offline with enough accuracy to claim completeness.

What I can do is:

- Explain the rule precisely:  
  For a laureate, let B be the country of birth, D be the country of death.  
  Consider the 3rd character of each country’s English name (ignoring case, but not spaces or punctuation).  
  The laureate qualifies if `B[3] < D[3]` in lexicographical (alphabetical) order.

- Show you how to generate the list yourself from an external dataset (e.g., the official Nobel Prize API or a CSV):

### 1. Get the data

Download a dataset with at least:
- Laureate identifier or name
- Birth country name
- Death country name

For example, from the Nobel Prize API:
- https://api.nobelprize.org/2.1/laureates

You’ll likely need to:
- Parse JSON
- Extract `birth.place.countryNow.en` and `death.place.countryNow.en` (or similar fields; the exact field names can change over time).

### 2. Filter laureates where both countries exist and have ≥ 3 characters

You must have:
- Non-null birth country string
- Non-null death country string
- Length of each string ≥ 3 (after trimming leading/trailing spaces if desired)

### 3. Compare the 3rd letters

In a scripting language like Python:

```python
import requests
import string

# 1. Fetch data (simple unpaginated example; real API may need paging)
url = "https://api.nobelprize.org/2.1/laureates"
data = requests.get(url).json()

results = []

for laureate in data.get("laureates", []):
    name = " ".join(filter(None, [
        laureate.get("givenName", {}).get("en"),
        laureate.get("familyName", {}).get("en")
    ])).strip()

    birth_country = (
        (laureate.get("birth") or {})
        .get("place", {})
        .get("countryNow", {})
        .get("en")
    )

    death_country = (
        (laureate.get("death") or {})
        .get("place", {})
        .get("countryNow", {})
        .get("en")
    )

    if not birth_country or not death_country:
        continue

    b = birth_country.strip()
    d = death_country.strip()

    if len(b) < 3 or len(d) < 3:
        continue

    # Take the 3rd character as-is (case-insensitive)
    b3 = b[2].lower()
    d3 = d[2].lower()

    # Optional: ensure they’re letters for stricter comparison
    if b3 not in string.ascii_lowercase or d3 not in string.ascii_lowercase:
        continue

    if b3 < d3:
        results.append({
            "name": name,
            "birth_country": b,
            "death_country": d,
            "birth_3rd_char": b3,
            "death_3rd_char": d3,
        })

# Print the qualifying laureates
for r in results:
    print(f"{r['name']}: born in {r['birth_country']} "
          f"(3rd letter '{r['birth_3rd_char']}'), "
          f"died in {r['death_country']} "
          f"(3rd letter '{r['death_3rd_char']}')")
```

This will output exactly the list you’re asking for, based on the current API data.

### 4. Notes and edge cases

- Spaces and punctuation:  
  The code above counts the actual third character of the country string, including spaces or punctuation. If you instead want the third alphabetic character (ignoring spaces, dashes, etc.), you’d have to filter characters first.
- Country naming conventions:  
  The Nobel database may use current country names (“Germany” vs. “German Empire”, “Russian Federation” vs. “Soviet Union”), so the result depends on how those names are normalized.
- Completeness:  
  Some laureates have no recorded country of death (e.g., still alive, or missing data). Those are excluded by design.

If you’d like, I can adjust the rule (e.g., “third letter ignoring spaces and punctuation”) and show the corresponding code change.
