Let's divide $10^{30}$ by 97. We can use the property that $100 \equiv 3 \pmod{97}$.
We have $10^{30} = (10^2)^{15} = (100)^{15} \equiv 3^{15} \pmod{97}$.

Now, $3^1 = 3$
$3^2 = 9$
$3^3 = 27$
$3^4 = 81 \equiv 81 - 97 = -16 \pmod{97}$
$3^5 = 3 \cdot 3^4 \equiv 3(-16) = -48 \pmod{97}$
$3^6 = (3^3)^2 = (27)^2 = 729 = 7 \cdot 97 + 50 \equiv 50 \pmod{97}$
$3^7 \equiv 3 \cdot 50 = 150 = 97 + 53 \equiv 53 \pmod{97}$
$3^8 = (3^4)^2 \equiv (-16)^2 = 256 = 2 \cdot 97 + 62 \equiv 62 \pmod{97}$
$3^9 = 3 \cdot 3^8 \equiv 3 \cdot 62 = 186 = 97 + 89 \equiv 89 \equiv -8 \pmod{97}$
$3^{10} = (3^5)^2 \equiv (-48)^2 = 2304 = 23 \cdot 97 + 73 \equiv 73 \equiv -24 \pmod{97}$

We have $3^{15} = 3^5 \cdot 3^{10} \equiv (-48)(-24) = 1152 = 11 \cdot 97 + 85 \equiv 85 \pmod{97}$.

So, $10^{30} \equiv 85 \pmod{97}$.
Then $10^{30} = 97k + 85$ for some integer $k$.
We need to compute $10^{30} / 97$, so we need to find the quotient $k$ and the remainder $85$.
$10^{30} = 1 \underbrace{00 \dots 0}_{30}$

We have $10^{30} = 97k + 85$.
$k = \frac{10^{30} - 85}{97}$

Let's perform long division of $10^{30}$ by 97.

We can write $10^{30} = 10^{30} - 85 + 85 = 97k + 85$.
$97k = 10^{30} - 85 = \underbrace{9 \dots 9}_{28} 15$
$k = \frac{10^{30} - 85}{97}$
$k = \frac{\underbrace{99 \dots 99}_{28} 15}{97} = \frac{\overbrace{100 \dots 00}^{30} - 85}{97}$
$10^{30} = 97 \times \underbrace{1030927835}_{10 digits} \times 10^{20} + \dots + 85$

The quotient is $\frac{10^{30}-85}{97}$ and the remainder is 85.
Since $10^{30}-85 = \underbrace{99 \dots 99}_{28}15$, we have
$k = \frac{\underbrace{99 \dots 99}_{28}15}{97}$
$k = 1030927835051546391752577319 \dots$.

Final Answer: The final answer is $\boxed{85}$
