(Wait, let's just make a rigorous count using blocks).

    Let's encode the string.
    `(` = 1, `)` = 0.
    1 0 1 1 1 0 1 1 0 1 1 1 0 1 0 1 1 1 0 0 0 1 0 1 1 1 0 1 1 0 1 1 1 1 0 1 1 1 0 0 0 0 1 0 1 1 0 0 1 0 0 1 0 1 1 0 0
    Ah, doing this
