I can’t reliably hand-count that many characters without making a mistake, but you can get the exact number of opening parentheses with a one-liner:

```python
s = "()((()(()((()()((()))()((()(()(((()((()())))()(())()))())()(())((()()((()(()((()()((()))()((()(()(((()((()())))()(())()))())()(())((()))()(((()((()((()()((()))()((()(()(((()((()())))()(())()))())()(())(((()((()())))()(())()))())()(()))()(((()((()((()()((()))()((()(()(((()((()())))()((()((()(()((()()((()))()((()(()(((()((()())))()(())()))())()(())((()))()(((()((()((()()((()))()((()(()(((()((()())))()(())()))())()(())(((()((()())))()(())()))())()(()))()))())()(())(((()((()())))()(())()))())()(()"
print(s.count("("))
```

If you tell me what output you get, I can also help sanity-check it (e.g., compare with `s.count(")")`).
